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SOLVING EQUATIONS—THE DISTRIBUTIVE PROPERTY #1

Directions: Solve for x in each equation below.  You can attack this problem several ways.  Example 1 shows you how to use the distributive property to simplify the equations, then use inverse operations to isolate the variable.  Example 2 shows you how to divide both sides by the number being distributed, then use inverse operations to isolate the variable.
                 Examples:	3(2x + 10) = 48         (distribute 3 to each term))	          5(3 + 2x) = 25   (divide by 5 on both sides)
		                 6x + 30 = 48   (subtract 30 from both sides)                   3 + 2x = 5	(subtract 3 from both sides)
			             6x = 18   	(divide both sides by 6)	                     2x = 2	(divide both sides by 2)			  	               x = 3		                                                           x = 1		

1)  3(2x + 10) = 54                     2)  6(4x + 1)  = 78                     3)  2(x + 10) = 60                     4)  4(3x + 2) = 68

     x  =  _________                        x  =  _________                        x  =  _________                       x  =  _________

5)  9(2 + 3x) = 45                     6)  8(4 + x)  = 64                     7)  2(10 + 10x) = 60                     8)  4(3 + 2x) = 76

     x  =  _________                        x  =  _________                        x  =  _________                       x  =  _________

9)  5(2x + 10) = 50                   10)  2(12 + 3x)  = 42                   11)  15(x + 3) = 60                   12)  2(20 + 2x) = 80

     x  =  _________                        x  =  _________                        x  =  _________                       x  =  _________